20b^2-72b+63=0

Solution for 20b^2-72b+63=0 equation:

20b^2-72b+63=0

a = 20; b = -72; c = +63;
Δ = b2-4ac
Δ = -722-4·20·63
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{144}=12$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-72)-12}{2*20}=\frac{60}{40}
=1+1/2
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-72)+12}{2*20}=\frac{84}{40}
=2+1/10
$